4x-12/x=28

Solution for 4x-12/x=28 equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x-(12/x) = 28 // - 28

4*x-(12/x)-28 = 0

4*x-12*x^-1-28 = 0

4*x^1-12*x^-1-28*x^0 = 0

(4*x^2-28*x^1-12*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^2-28*x^1-12*x^0) = 0

x^1

4*x^2-28*x-12 = 0

4*x^2-28*x-12 = 0

DELTA = (-28)^2-(-12*4*4)

DELTA = 976

DELTA > 0

x = (976^(1/2)+28)/(2*4) or x = (28-976^(1/2))/(2*4)

x = (4*61^(1/2)+28)/8 or x = (28-4*61^(1/2))/8

x in { (28-4*61^(1/2))/8, (4*61^(1/2)+28)/8} 

x in { (28-4*61^(1/2))/8, (4*61^(1/2)+28)/8 }