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4x-1/3x=-13
We move all terms to the left:
4x-1/3x-(-13)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
4x-1/3x+13=0
We multiply all the terms by the denominator
4x*3x+13*3x-1=0
Wy multiply elements
12x^2+39x-1=0
a = 12; b = 39; c = -1;
Δ = b2-4ac
Δ = 392-4·12·(-1)
Δ = 1569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-\sqrt{1569}}{2*12}=\frac{-39-\sqrt{1569}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+\sqrt{1569}}{2*12}=\frac{-39+\sqrt{1569}}{24} $
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