4x-(6-x)+2=1/2(2-10x)

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Solution for 4x-(6-x)+2=1/2(2-10x) equation: 



4x-(6-x)+2=1/2(2-10x)

We move all terms to the left:

4x-(6-x)+2-(1/2(2-10x))=0



Domain of the equation: 2(2-10x))!=0

x∈R



We add all the numbers together, and all the variables

4x-(-1x+6)-(1/2(-10x+2))+2=0

We get rid of parentheses

4x+1x-(1/2(-10x+2))-6+2=0

We multiply all the terms by the denominator


4x*2(-10x+2))+1x*2(-10x-10x+2))+2*2(-10x+2))+2))-(1-6*2(=0

We add all the numbers together, and all the variables

4x*2(-10x+2))+1x*2(-20x+2))+2*2(-10x+2))+2))-(1-6*2(=0

We add all the numbers together, and all the variables

-20x+4x*2(-10x+2))+1x*2(+2))+2*2(-10x+2))+2))-(1-6*2(=0

Wy multiply elements

16x^3(-+2))+2*2(-20x-10x+2))+2))-(1-6*2(=0

We do not support expression: x^3(

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