4x+6/3x+1+4x-6/x-10

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Solution for 4x+6/3x+1+4x-6/x-10 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x+(6/3)*x+4*x-(6/x)-10+1 = 0

4*x+(6/3)*x+4*x-6*x^-1-10+1 = 0

10*x^1-6*x^-1-9*x^0 = 0

(10*x^2-9*x^1-6*x^0)/(x^1) = 0 // * x^2

x^1*(10*x^2-9*x^1-6*x^0) = 0

x^1

10*x^2-9*x-6 = 0

10*x^2-9*x-6 = 0

DELTA = (-9)^2-(-6*4*10)

DELTA = 321

DELTA > 0

x = (321^(1/2)+9)/(2*10) or x = (9-321^(1/2))/(2*10)

x = (321^(1/2)+9)/20 or x = (9-321^(1/2))/20

x in { (9-321^(1/2))/20, (321^(1/2)+9)/20} 

x in { (9-321^(1/2))/20, (321^(1/2)+9)/20 }

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