4x+5x-48=64-7x

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Solution for 4x+5x-48=64-7x equation: 



4x+5x-48=64-7x

We move all terms to the left:

4x+5x-48-(64-7x)=0

We add all the numbers together, and all the variables

4x+5x-(-7x+64)-48=0

We add all the numbers together, and all the variables

9x-(-7x+64)-48=0

We get rid of parentheses

9x+7x-64-48=0

We add all the numbers together, and all the variables

16x-112=0

We move all terms containing x to the left, all other terms to the right

16x=112

x=112/16

x=7

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