4x+5x-2=-2(8-x)x=

Solution for 4x+5x-2=-2(8-x)x= equation:

4x+5x-2=-2(8-x)x=

We move all terms to the left:

4x+5x-2-(-2(8-x)x)=0

We add all the numbers together, and all the variables

4x+5x-(-2(-1x+8)x)-2=0

We add all the numbers together, and all the variables

9x-(-2(-1x+8)x)-2=0


We calculate terms in parentheses: -(-2(-1x+8)x), so:

-2(-1x+8)x

We multiply parentheses

2x^2-16x

Back to the equation:

-(2x^2-16x)


We get rid of parentheses

-2x^2+9x+16x-2=0

We add all the numbers together, and all the variables

-2x^2+25x-2=0

a = -2; b = 25; c = -2;
Δ = b2-4ac
Δ = 252-4·(-2)·(-2)
Δ = 609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{609}}{2*-2}=\frac{-25-\sqrt{609}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{609}}{2*-2}=\frac{-25+\sqrt{609}}{-4}
$