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4x+5=2/39x
We move all terms to the left:
4x+5-(2/39x)=0
Domain of the equation: 39x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4x-(+2/39x)+5=0
We get rid of parentheses
4x-2/39x+5=0
We multiply all the terms by the denominator
4x*39x+5*39x-2=0
Wy multiply elements
156x^2+195x-2=0
a = 156; b = 195; c = -2;
Δ = b2-4ac
Δ = 1952-4·156·(-2)
Δ = 39273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(195)-\sqrt{39273}}{2*156}=\frac{-195-\sqrt{39273}}{312} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(195)+\sqrt{39273}}{2*156}=\frac{-195+\sqrt{39273}}{312} $
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