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4x+5=1/2x-2
We move all terms to the left:
4x+5-(1/2x-2)=0
Domain of the equation: 2x-2)!=0We get rid of parentheses
x∈R
4x-1/2x+2+5=0
We multiply all the terms by the denominator
4x*2x+2*2x+5*2x-1=0
Wy multiply elements
8x^2+4x+10x-1=0
We add all the numbers together, and all the variables
8x^2+14x-1=0
a = 8; b = 14; c = -1;
Δ = b2-4ac
Δ = 142-4·8·(-1)
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{57}}{2*8}=\frac{-14-2\sqrt{57}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{57}}{2*8}=\frac{-14+2\sqrt{57}}{16} $
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