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4x+5=(1/2)9x+3
We move all terms to the left:
4x+5-((1/2)9x+3)=0
Domain of the equation: 2)9x+3)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4x-((+1/2)9x+3)+5=0
We multiply all the terms by the denominator
4x*2)9x+3)-((+5*2)9x+3)+1=0
We add all the numbers together, and all the variables
4x*2)9x+3)-(109x+3)+1=0
Wy multiply elements
8x^2=0
a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{16}=0$
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