4x+5(7x-3)=9(x-5)-3(2x-1)

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Solution for 4x+5(7x-3)=9(x-5)-3(2x-1) equation: 



4x+5(7x-3)=9(x-5)-3(2x-1)

We move all terms to the left:

4x+5(7x-3)-(9(x-5)-3(2x-1))=0

We multiply parentheses

4x+35x-(9(x-5)-3(2x-1))-15=0



We calculate terms in parentheses: -(9(x-5)-3(2x-1)), so:

9(x-5)-3(2x-1)

We multiply parentheses

9x-6x-45+3

We add all the numbers together, and all the variables

3x-42

Back to the equation:

-(3x-42)



We add all the numbers together, and all the variables

39x-(3x-42)-15=0

We get rid of parentheses

39x-3x+42-15=0

We add all the numbers together, and all the variables

36x+27=0

We move all terms containing x to the left, all other terms to the right

36x=-27

x=-27/36

x=-3/4

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