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4x+39=3x+5(2+6x)
We move all terms to the left:
4x+39-(3x+5(2+6x))=0
We add all the numbers together, and all the variables
4x-(3x+5(6x+2))+39=0
We calculate terms in parentheses: -(3x+5(6x+2)), so:We get rid of parentheses
3x+5(6x+2)
We multiply parentheses
3x+30x+10
We add all the numbers together, and all the variables
33x+10
Back to the equation:
-(33x+10)
4x-33x-10+39=0
We add all the numbers together, and all the variables
-29x+29=0
We move all terms containing x to the left, all other terms to the right
-29x=-29
x=-29/-29
x=1
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