4x+35=11(x+2)-22

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Solution for 4x+35=11(x+2)-22 equation: 



4x+35=11(x+2)-22

We move all terms to the left:

4x+35-(11(x+2)-22)=0



We calculate terms in parentheses: -(11(x+2)-22), so:

11(x+2)-22

We multiply parentheses

11x+22-22

We add all the numbers together, and all the variables

11x

Back to the equation:

-(11x)



We add all the numbers together, and all the variables

-7x+35=0

We move all terms containing x to the left, all other terms to the right

-7x=-35

x=-35/-7

x=+5

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