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4x+3/2x=13
We move all terms to the left:
4x+3/2x-(13)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
4x*2x-13*2x+3=0
Wy multiply elements
8x^2-26x+3=0
a = 8; b = -26; c = +3;
Δ = b2-4ac
Δ = -262-4·8·3
Δ = 580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{580}=\sqrt{4*145}=\sqrt{4}*\sqrt{145}=2\sqrt{145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{145}}{2*8}=\frac{26-2\sqrt{145}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{145}}{2*8}=\frac{26+2\sqrt{145}}{16} $
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