4x+3(x-2)=9(x-1)+1

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Solution for 4x+3(x-2)=9(x-1)+1 equation: 



4x+3(x-2)=9(x-1)+1

We move all terms to the left:

4x+3(x-2)-(9(x-1)+1)=0

We multiply parentheses

4x+3x-(9(x-1)+1)-6=0



We calculate terms in parentheses: -(9(x-1)+1), so:

9(x-1)+1

We multiply parentheses

9x-9+1

We add all the numbers together, and all the variables

9x-8

Back to the equation:

-(9x-8)



We add all the numbers together, and all the variables

7x-(9x-8)-6=0

We get rid of parentheses

7x-9x+8-6=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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