4x+3(x+3)=20-(x-5)

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Solution for 4x+3(x+3)=20-(x-5) equation: 



4x+3(x+3)=20-(x-5)

We move all terms to the left:

4x+3(x+3)-(20-(x-5))=0

We multiply parentheses

4x+3x-(20-(x-5))+9=0



We calculate terms in parentheses: -(20-(x-5)), so:

20-(x-5)

determiningTheFunctionDomain
-(x-5)+20

We get rid of parentheses

-x+5+20

We add all the numbers together, and all the variables

-1x+25

Back to the equation:

-(-1x+25)



We add all the numbers together, and all the variables

7x-(-1x+25)+9=0

We get rid of parentheses

7x+1x-25+9=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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