4x+3(x+1)=2(x-1)+15

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Solution for 4x+3(x+1)=2(x-1)+15 equation: 



4x+3(x+1)=2(x-1)+15

We move all terms to the left:

4x+3(x+1)-(2(x-1)+15)=0

We multiply parentheses

4x+3x-(2(x-1)+15)+3=0



We calculate terms in parentheses: -(2(x-1)+15), so:

2(x-1)+15

We multiply parentheses

2x-2+15

We add all the numbers together, and all the variables

2x+13

Back to the equation:

-(2x+13)



We add all the numbers together, and all the variables

7x-(2x+13)+3=0

We get rid of parentheses

7x-2x-13+3=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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