4x+3(4x+4)=4(7x+3)-3

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Solution for 4x+3(4x+4)=4(7x+3)-3 equation: 



4x+3(4x+4)=4(7x+3)-3

We move all terms to the left:

4x+3(4x+4)-(4(7x+3)-3)=0

We multiply parentheses

4x+12x-(4(7x+3)-3)+12=0



We calculate terms in parentheses: -(4(7x+3)-3), so:

4(7x+3)-3

We multiply parentheses

28x+12-3

We add all the numbers together, and all the variables

28x+9

Back to the equation:

-(28x+9)



We add all the numbers together, and all the variables

16x-(28x+9)+12=0

We get rid of parentheses

16x-28x-9+12=0

We add all the numbers together, and all the variables

-12x+3=0

We move all terms containing x to the left, all other terms to the right

-12x=-3

x=-3/-12

x=1/4

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