4x+3(1+6x)=135

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Solution for 4x+3(1+6x)=135 equation: 



4x+3(1+6x)=135

We move all terms to the left:

4x+3(1+6x)-(135)=0

We add all the numbers together, and all the variables

4x+3(6x+1)-135=0

We multiply parentheses

4x+18x+3-135=0

We add all the numbers together, and all the variables

22x-132=0

We move all terms containing x to the left, all other terms to the right

22x=132

x=132/22

x=6

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