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4x+2x=-1/2x+10
We move all terms to the left:
4x+2x-(-1/2x+10)=0
Domain of the equation: 2x+10)!=0We add all the numbers together, and all the variables
x∈R
6x-(-1/2x+10)=0
We get rid of parentheses
6x+1/2x-10=0
We multiply all the terms by the denominator
6x*2x-10*2x+1=0
Wy multiply elements
12x^2-20x+1=0
a = 12; b = -20; c = +1;
Δ = b2-4ac
Δ = -202-4·12·1
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{22}}{2*12}=\frac{20-4\sqrt{22}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{22}}{2*12}=\frac{20+4\sqrt{22}}{24} $
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