4x+28=12x-40

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Solution for 4x+28=12x-40 equation: 



4x+28=12x-40

We move all terms to the left:

4x+28-(12x-40)=0

We get rid of parentheses

4x-12x+40+28=0

We add all the numbers together, and all the variables

-8x+68=0

We move all terms containing x to the left, all other terms to the right

-8x=-68

x=-68/-8

x=8+1/2

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