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4x+2/5x+4=25
We move all terms to the left:
4x+2/5x+4-(25)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
4x+2/5x-21=0
We multiply all the terms by the denominator
4x*5x-21*5x+2=0
Wy multiply elements
20x^2-105x+2=0
a = 20; b = -105; c = +2;
Δ = b2-4ac
Δ = -1052-4·20·2
Δ = 10865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-\sqrt{10865}}{2*20}=\frac{105-\sqrt{10865}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+\sqrt{10865}}{2*20}=\frac{105+\sqrt{10865}}{40} $
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