4x+2(x-5)+12=7(x-12)+4(x-5)

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Solution for 4x+2(x-5)+12=7(x-12)+4(x-5) equation: 



4x+2(x-5)+12=7(x-12)+4(x-5)

We move all terms to the left:

4x+2(x-5)+12-(7(x-12)+4(x-5))=0

We multiply parentheses

4x+2x-(7(x-12)+4(x-5))-10+12=0



We calculate terms in parentheses: -(7(x-12)+4(x-5)), so:

7(x-12)+4(x-5)

We multiply parentheses

7x+4x-84-20

We add all the numbers together, and all the variables

11x-104

Back to the equation:

-(11x-104)



We add all the numbers together, and all the variables

6x-(11x-104)+2=0

We get rid of parentheses

6x-11x+104+2=0

We add all the numbers together, and all the variables

-5x+106=0

We move all terms containing x to the left, all other terms to the right

-5x=-106

x=-106/-5

x=21+1/5

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