4x+2(x-4)=8(x-1)-2x

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Solution for 4x+2(x-4)=8(x-1)-2x equation: 



4x+2(x-4)=8(x-1)-2x

We move all terms to the left:

4x+2(x-4)-(8(x-1)-2x)=0

We multiply parentheses

4x+2x-(8(x-1)-2x)-8=0



We calculate terms in parentheses: -(8(x-1)-2x), so:

8(x-1)-2x

We add all the numbers together, and all the variables

-2x+8(x-1)

We multiply parentheses

-2x+8x-8

We add all the numbers together, and all the variables

6x-8

Back to the equation:

-(6x-8)



We add all the numbers together, and all the variables

6x-(6x-8)-8=0

We get rid of parentheses

6x-6x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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