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4x+2(x-4)=2(x-5)+5
We move all terms to the left:
4x+2(x-4)-(2(x-5)+5)=0
We multiply parentheses
4x+2x-(2(x-5)+5)-8=0
We calculate terms in parentheses: -(2(x-5)+5), so:We add all the numbers together, and all the variables
2(x-5)+5
We multiply parentheses
2x-10+5
We add all the numbers together, and all the variables
2x-5
Back to the equation:
-(2x-5)
6x-(2x-5)-8=0
We get rid of parentheses
6x-2x+5-8=0
We add all the numbers together, and all the variables
4x-3=0
We move all terms containing x to the left, all other terms to the right
4x=3
x=3/4
x=3/4
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