4x+2(x-4)-3=(3x-5)-1

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Solution for 4x+2(x-4)-3=(3x-5)-1 equation: 



4x+2(x-4)-3=(3x-5)-1

We move all terms to the left:

4x+2(x-4)-3-((3x-5)-1)=0

We multiply parentheses

4x+2x-((3x-5)-1)-8-3=0



We calculate terms in parentheses: -((3x-5)-1), so:

(3x-5)-1

We get rid of parentheses

3x-5-1

We add all the numbers together, and all the variables

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

6x-(3x-6)-11=0

We get rid of parentheses

6x-3x+6-11=0

We add all the numbers together, and all the variables

3x-5=0

We move all terms containing x to the left, all other terms to the right

3x=5

x=5/3

x=1+2/3

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