4x+1=(1/3x)+10

Solution for 4x+1=(1/3x)+10 equation:

4x+1=(1/3x)+10

We move all terms to the left:

4x+1-((1/3x)+10)=0


Domain of the equation: 3x)+10)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4x-((+1/3x)+10)+1=0

We multiply all the terms by the denominator


4x*3x)+10)-((+1*3x)+10)+1=0

Wy multiply elements

12x^2+3x=0

a = 12; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·12·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*12}=\frac{-6}{24}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*12}=\frac{0}{24}
=0
$