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4x+14=2/1(1+3x
We move all terms to the left:
4x+14-(2/1(1+3x)=0
Domain of the equation: 1(1+3x)+14!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
1(1+3x)!=-14
x∈R
4x-(2/1(3x+1)+14=0
We multiply all the terms by the denominator
4x*1(3x+1)+14-(2=0
We add all the numbers together, and all the variables
4x*1(3x+1)=0
Wy multiply elements
4x^2(3=0
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