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4x+12=3(x+3)+4
We move all terms to the left:
4x+12-(3(x+3)+4)=0
We calculate terms in parentheses: -(3(x+3)+4), so:We get rid of parentheses
3(x+3)+4
We multiply parentheses
3x+9+4
We add all the numbers together, and all the variables
3x+13
Back to the equation:
-(3x+13)
4x-3x-13+12=0
We add all the numbers together, and all the variables
x-1=0
We move all terms containing x to the left, all other terms to the right
x=1
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