4x+120=2(80+x)

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Solution for 4x+120=2(80+x) equation: 



4x+120=2(80+x)

We move all terms to the left:

4x+120-(2(80+x))=0

We add all the numbers together, and all the variables

4x-(2(x+80))+120=0



We calculate terms in parentheses: -(2(x+80)), so:

2(x+80)

We multiply parentheses

2x+160

Back to the equation:

-(2x+160)



We get rid of parentheses

4x-2x-160+120=0

We add all the numbers together, and all the variables

2x-40=0

We move all terms containing x to the left, all other terms to the right

2x=40

x=40/2

x=20

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