4x+10=(1/2)17x-43

Solution for 4x+10=(1/2)17x-43 equation:

4x+10=(1/2)17x-43

We move all terms to the left:

4x+10-((1/2)17x-43)=0


Domain of the equation: 2)17x-43)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4x-((+1/2)17x-43)+10=0

We multiply all the terms by the denominator


4x*2)17x-43)-((+10*2)17x-43)+1=0

We add all the numbers together, and all the variables

4x*2)17x-43)-(2017x-43)+1=0

Wy multiply elements

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$