4x+1/2x-5=9

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Solution for 4x+1/2x-5=9 equation:



4x+1/2x-5=9
We move all terms to the left:
4x+1/2x-5-(9)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We add all the numbers together, and all the variables
4x+1/2x-14=0
We multiply all the terms by the denominator
4x*2x-14*2x+1=0
Wy multiply elements
8x^2-28x+1=0
a = 8; b = -28; c = +1;
Δ = b2-4ac
Δ = -282-4·8·1
Δ = 752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{752}=\sqrt{16*47}=\sqrt{16}*\sqrt{47}=4\sqrt{47}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{47}}{2*8}=\frac{28-4\sqrt{47}}{16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{47}}{2*8}=\frac{28+4\sqrt{47}}{16} $

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