4x+1/2(8x-+6)=2(4x+3)

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Solution for 4x+1/2(8x-+6)=2(4x+3) equation: 



4x+1/2(8x-+6)=2(4x+3)

We move all terms to the left:

4x+1/2(8x-+6)-(2(4x+3))=0



Domain of the equation: 2(8x-+6)!=0

x∈R



We add all the numbers together, and all the variables

4x+1/2(+8x)-(2(4x+3))=0

We multiply all the terms by the denominator


4x*2(+8x)-((2(4x+3)))*2(+8x)+1=0



We calculate terms in parentheses: -((2(4x+3)))*2(+8x), so:

(2(4x+3)))*2(+8x

We add all the numbers together, and all the variables

8x+(2(4x+3)))*2(

Back to the equation:

-(8x+(2(4x+3)))*2()



Wy multiply elements

8x^2(+-(8x+(2(4x+3)))*2()+1=0

We use the square of the difference formula

8x^2(-(8x+(2(4x+3)))*2()+1=0

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