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4x+(6+x)2=2x+(2+x)
We move all terms to the left:
4x+(6+x)2-(2x+(2+x))=0
We add all the numbers together, and all the variables
4x+(x+6)2-(2x+(x+2))=0
We multiply parentheses
4x+2x-(2x+(x+2))+12=0
We calculate terms in parentheses: -(2x+(x+2)), so:We add all the numbers together, and all the variables
2x+(x+2)
We get rid of parentheses
2x+x+2
We add all the numbers together, and all the variables
3x+2
Back to the equation:
-(3x+2)
6x-(3x+2)+12=0
We get rid of parentheses
6x-3x-2+12=0
We add all the numbers together, and all the variables
3x+10=0
We move all terms containing x to the left, all other terms to the right
3x=-10
x=-10/3
x=-3+1/3
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