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4x+(3x-2)-(2x+5)=-(3-x)
We move all terms to the left:
4x+(3x-2)-(2x+5)-(-(3-x))=0
We add all the numbers together, and all the variables
4x+(3x-2)-(2x+5)-(-(-1x+3))=0
We get rid of parentheses
4x+3x-2x-(-(-1x+3))-2-5=0
We calculate terms in parentheses: -(-(-1x+3)), so:We add all the numbers together, and all the variables
-(-1x+3)
We get rid of parentheses
1x-3
We add all the numbers together, and all the variables
x-3
Back to the equation:
-(x-3)
5x-(x-3)-7=0
We get rid of parentheses
5x-x+3-7=0
We add all the numbers together, and all the variables
4x-4=0
We move all terms containing x to the left, all other terms to the right
4x=4
x=4/4
x=1
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