4x+(3x+1)=6-2(x-1)

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Solution for 4x+(3x+1)=6-2(x-1) equation: 



4x+(3x+1)=6-2(x-1)

We move all terms to the left:

4x+(3x+1)-(6-2(x-1))=0

We get rid of parentheses

4x+3x-(6-2(x-1))+1=0



We calculate terms in parentheses: -(6-2(x-1)), so:

6-2(x-1)

determiningTheFunctionDomain
-2(x-1)+6

We multiply parentheses

-2x+2+6

We add all the numbers together, and all the variables

-2x+8

Back to the equation:

-(-2x+8)



We add all the numbers together, and all the variables

7x-(-2x+8)+1=0

We get rid of parentheses

7x+2x-8+1=0

We add all the numbers together, and all the variables

9x-7=0

We move all terms containing x to the left, all other terms to the right

9x=7

x=7/9

x=7/9

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