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4x*x=4000
We move all terms to the left:
4x*x-(4000)=0
Wy multiply elements
4x^2-4000=0
a = 4; b = 0; c = -4000;
Δ = b2-4ac
Δ = 02-4·4·(-4000)
Δ = 64000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{64000}=\sqrt{6400*10}=\sqrt{6400}*\sqrt{10}=80\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{10}}{2*4}=\frac{0-80\sqrt{10}}{8} =-\frac{80\sqrt{10}}{8} =-10\sqrt{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{10}}{2*4}=\frac{0+80\sqrt{10}}{8} =\frac{80\sqrt{10}}{8} =10\sqrt{10} $
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