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4x*7x=12600
We move all terms to the left:
4x*7x-(12600)=0
Wy multiply elements
28x^2-12600=0
a = 28; b = 0; c = -12600;
Δ = b2-4ac
Δ = 02-4·28·(-12600)
Δ = 1411200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1411200}=\sqrt{705600*2}=\sqrt{705600}*\sqrt{2}=840\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-840\sqrt{2}}{2*28}=\frac{0-840\sqrt{2}}{56} =-\frac{840\sqrt{2}}{56} =-15\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+840\sqrt{2}}{2*28}=\frac{0+840\sqrt{2}}{56} =\frac{840\sqrt{2}}{56} =15\sqrt{2} $
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