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4x*3x=240
We move all terms to the left:
4x*3x-(240)=0
Wy multiply elements
12x^2-240=0
a = 12; b = 0; c = -240;
Δ = b2-4ac
Δ = 02-4·12·(-240)
Δ = 11520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11520}=\sqrt{2304*5}=\sqrt{2304}*\sqrt{5}=48\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{5}}{2*12}=\frac{0-48\sqrt{5}}{24} =-\frac{48\sqrt{5}}{24} =-2\sqrt{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{5}}{2*12}=\frac{0+48\sqrt{5}}{24} =\frac{48\sqrt{5}}{24} =2\sqrt{5} $
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