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4x*2x=448
We move all terms to the left:
4x*2x-(448)=0
Wy multiply elements
8x^2-448=0
a = 8; b = 0; c = -448;
Δ = b2-4ac
Δ = 02-4·8·(-448)
Δ = 14336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14336}=\sqrt{1024*14}=\sqrt{1024}*\sqrt{14}=32\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{14}}{2*8}=\frac{0-32\sqrt{14}}{16} =-\frac{32\sqrt{14}}{16} =-2\sqrt{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{14}}{2*8}=\frac{0+32\sqrt{14}}{16} =\frac{32\sqrt{14}}{16} =2\sqrt{14} $
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