4x(x-6)-13=(4x-5)(x-3)

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Solution for 4x(x-6)-13=(4x-5)(x-3) equation: 



4x(x-6)-13=(4x-5)(x-3)

We move all terms to the left:

4x(x-6)-13-((4x-5)(x-3))=0

We multiply parentheses

4x^2-24x-((4x-5)(x-3))-13=0

We multiply parentheses ..

4x^2-((+4x^2-12x-5x+15))-24x-13=0



We calculate terms in parentheses: -((+4x^2-12x-5x+15)), so:

(+4x^2-12x-5x+15)

We get rid of parentheses

4x^2-12x-5x+15

We add all the numbers together, and all the variables

4x^2-17x+15

Back to the equation:

-(4x^2-17x+15)



We add all the numbers together, and all the variables

4x^2-24x-(4x^2-17x+15)-13=0

We get rid of parentheses

4x^2-4x^2-24x+17x-15-13=0

We add all the numbers together, and all the variables

-7x-28=0

We move all terms containing x to the left, all other terms to the right

-7x=28

x=28/-7

x=-4

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