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4x(x-4)+4-10x=30
We move all terms to the left:
4x(x-4)+4-10x-(30)=0
We add all the numbers together, and all the variables
-10x+4x(x-4)-26=0
We multiply parentheses
4x^2-10x-16x-26=0
We add all the numbers together, and all the variables
4x^2-26x-26=0
a = 4; b = -26; c = -26;
Δ = b2-4ac
Δ = -262-4·4·(-26)
Δ = 1092
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1092}=\sqrt{4*273}=\sqrt{4}*\sqrt{273}=2\sqrt{273}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{273}}{2*4}=\frac{26-2\sqrt{273}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{273}}{2*4}=\frac{26+2\sqrt{273}}{8} $
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