4x(x-3)=(x+3)(x-3)

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Solution for 4x(x-3)=(x+3)(x-3) equation: 



4x(x-3)=(x+3)(x-3)

We move all terms to the left:

4x(x-3)-((x+3)(x-3))=0

We use the square of the difference formula

x^2+4x(x-3)+9=0

We multiply parentheses

x^2+4x^2-12x+9=0

We add all the numbers together, and all the variables

5x^2-12x+9=0

a = 5; b = -12; c = +9;
Δ = b2-4ac
Δ = -122-4·5·9
Δ = -36
Delta is less than zero, so there is no solution for the equation

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