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4x(x-1)=2x+5+3x
We move all terms to the left:
4x(x-1)-(2x+5+3x)=0
We add all the numbers together, and all the variables
4x(x-1)-(5x+5)=0
We multiply parentheses
4x^2-4x-(5x+5)=0
We get rid of parentheses
4x^2-4x-5x-5=0
We add all the numbers together, and all the variables
4x^2-9x-5=0
a = 4; b = -9; c = -5;
Δ = b2-4ac
Δ = -92-4·4·(-5)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{161}}{2*4}=\frac{9-\sqrt{161}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{161}}{2*4}=\frac{9+\sqrt{161}}{8} $
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