4x(x+7)=20

Solution for 4x(x+7)=20 equation:

4x(x+7)=20

We move all terms to the left:

4x(x+7)-(20)=0

We multiply parentheses

4x^2+28x-20=0

a = 4; b = 28; c = -20;
Δ = b2-4ac
Δ = 282-4·4·(-20)
Δ = 1104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1104}=\sqrt{16*69}=\sqrt{16}*\sqrt{69}=4\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4\sqrt{69}}{2*4}=\frac{-28-4\sqrt{69}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4\sqrt{69}}{2*4}=\frac{-28+4\sqrt{69}}{8}
$