4x(x+2)x(x+5)=280

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Solution for 4x(x+2)x(x+5)=280 equation:


Simplifying
4x(x + 2) * x(x + 5) = 280

Reorder the terms:
4x(2 + x) * x(x + 5) = 280

Reorder the terms:
4x(2 + x) * x(5 + x) = 280

Reorder the terms for easier multiplication:
4x * x(2 + x)(5 + x) = 280

Multiply x * x
4x2(2 + x)(5 + x) = 280

Multiply (2 + x) * (5 + x)
4x2(2(5 + x) + x(5 + x)) = 280
4x2((5 * 2 + x * 2) + x(5 + x)) = 280
4x2((10 + 2x) + x(5 + x)) = 280
4x2(10 + 2x + (5 * x + x * x)) = 280
4x2(10 + 2x + (5x + x2)) = 280

Combine like terms: 2x + 5x = 7x
4x2(10 + 7x + x2) = 280
(10 * 4x2 + 7x * 4x2 + x2 * 4x2) = 280
(40x2 + 28x3 + 4x4) = 280

Solving
40x2 + 28x3 + 4x4 = 280

Solving for variable 'x'.

Reorder the terms:
-280 + 40x2 + 28x3 + 4x4 = 280 + -280

Combine like terms: 280 + -280 = 0
-280 + 40x2 + 28x3 + 4x4 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(-70 + 10x2 + 7x3 + x4) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-70 + 10x2 + 7x3 + x4)' equal to zero and attempt to solve: Simplifying -70 + 10x2 + 7x3 + x4 = 0 Solving -70 + 10x2 + 7x3 + x4 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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