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4x(x+2)/3=x-1
We move all terms to the left:
4x(x+2)/3-(x-1)=0
We get rid of parentheses
4x(x+2)/3-x+1=0
We multiply all the terms by the denominator
4x(x+2)-x*3+1*3=0
We add all the numbers together, and all the variables
4x(x+2)-x*3+3=0
We multiply parentheses
4x^2+8x-x*3+3=0
Wy multiply elements
4x^2+8x-3x+3=0
We add all the numbers together, and all the variables
4x^2+5x+3=0
a = 4; b = 5; c = +3;
Δ = b2-4ac
Δ = 52-4·4·3
Δ = -23
Delta is less than zero, so there is no solution for the equation
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