4x(x+1)=(2x-5)(2x+5)

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Solution for 4x(x+1)=(2x-5)(2x+5) equation: 



4x(x+1)=(2x-5)(2x+5)

We move all terms to the left:

4x(x+1)-((2x-5)(2x+5))=0

We use the square of the difference formula

4x^2+4x(x+1)+25=0

We multiply parentheses

4x^2+4x^2+4x+25=0

We add all the numbers together, and all the variables

8x^2+4x+25=0

a = 8; b = 4; c = +25;
Δ = b2-4ac
Δ = 42-4·8·25
Δ = -784
Delta is less than zero, so there is no solution for the equation

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