4x(9x=5)

Solution for 4x(9x=5) equation:

4x(9x=5)

We move all terms to the left:

4x(9x-(5))=0

We multiply parentheses

36x^2-20x=0

a = 36; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·36·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*36}=\frac{0}{72}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*36}=\frac{40}{72}
=5/9
$