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4x(9x+5)=3x
We move all terms to the left:
4x(9x+5)-(3x)=0
We add all the numbers together, and all the variables
-3x+4x(9x+5)=0
We multiply parentheses
36x^2-3x+20x=0
We add all the numbers together, and all the variables
36x^2+17x=0
a = 36; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·36·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*36}=\frac{-34}{72} =-17/36 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*36}=\frac{0}{72} =0 $
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