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4x(7x+2)=99
We move all terms to the left:
4x(7x+2)-(99)=0
We multiply parentheses
28x^2+8x-99=0
a = 28; b = 8; c = -99;
Δ = b2-4ac
Δ = 82-4·28·(-99)
Δ = 11152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11152}=\sqrt{16*697}=\sqrt{16}*\sqrt{697}=4\sqrt{697}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{697}}{2*28}=\frac{-8-4\sqrt{697}}{56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{697}}{2*28}=\frac{-8+4\sqrt{697}}{56} $
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